Question

A line is passing through the points (2,2) and is perpendicular to the line 3x+y=3 find its equation

Answer 1

Answer:

Step-by-step explanation:

Any line perpendicular to 3x+y=33x+y=3 is x−3y=kx−3y=k

It passes through (2,2)(2,2)

∴2−6=k∴2−6=k

k=−4k=−4

line is x−3y=4x−3y=4

Put x=0x=0 we get 3y=43y=4

i.e y=43y=43

y -intercept =43

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