A line is perpendicular to 5x + 2y - 8 = 0 and has the same y-intercept as x + 4y - 12 =0. Find the equation for the line.
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Step-by-step explanation:
5x+2y-8=0
2y=-5x+8 Divide with 2
y=(-5/2)x+4
Slope is dy/dx
dy/dx=-5/2
x+4y-12=0 for x=0
4y-12=0
4y=12 Divide with 4
y=3 y-intercept
Line equation:
y = mx + b
This is called the slope-intercept form because "m" is the slope and "b" gives the y-intercept.
m-5/2 b=3
Euation for the your line:
y=(-5/2)x+3
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I think this the right answer
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