A line is perpendicular to the line 3x + 2y - 1 = 0 and passes through the point
A(1,1). Find its equation.
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Given,
Line perpendicular to the line 3x+2y-1=0,
the line passes through(1,1) point.
To Find,
Equation of the line.
Solution,
First we have to calculate the slope of the line.
Slope of the line3x+2y-1=0 is-3/2.
Here the required line is perpendicular to it.
The other line is perpendicular means product of the slope of both should be 1.
So slope of required line=2/3
Required line passes through the point A(1,1).
So it's equation is given by the formula
⇒(y-y1)=m(x-x1)
⇒(y-1)=2/3(x-1)
⇒3y-3=2x-2
⇒2x-3y+1=0
Hence, the required equation is 2x-3y+1=0.
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