Question

A line is perpendicular to the line 3x + 2y - 1 = 0 and passes through the point
A(1,1). Find its equation.
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Answer 1

Answer:

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Answer 2

Given,

Line perpendicular to the line 3x+2y-1=0,

the line passes through(1,1) point.

To Find,

Equation of the line.

Solution,

First we have to calculate the slope of the line.

Slope of the line3x+2y-1=0 is-3/2.

Here the required line is perpendicular to it.

The other line is perpendicular means product of the slope of both should be 1.

So slope of required line=2/3

Required line passes through the point A(1,1).

So it's equation is given by the formula

⇒(y-y1)=m(x-x1)

⇒(y-1)=2/3(x-1)

⇒3y-3=2x-2

⇒2x-3y+1=0

Hence, the required equation is 2x-3y+1=0.