Question

A line is such that its segment
between the lines
5x-y+4= 0 and 3x + 4y - 4 = 0 is bisected at the point (1,5). Obtain its equation.​

Answer 1

Answer:

$\huge\sf\tt\red{AnSwEr}$

5x-y--4=0

y=5x-4

Putting values x=1 y=+1

3x+4y=0

4y=--3x

x=1 y = -3/4

Solving the given equations

5x-4y =4

3x+4y=4

x=20/3

Y= 8/23

Intersecting point of2 given equations and 2 strait lines

(X=20/3 y=8/23)

p (1,5)

Slope m of the linebisecting such = y-y1/x-x1 =( 5--8/23 )/1--20/3

= 127/23 /--17/23 =--127/17