Math, asked by cool21, 1 year ago

A line passes through (2,2) and is perpendicular to the line 3x+y=3 its y intercept is a) 1/3 b) 2/3 c) 1 d) 4/3

Answers

Answered by harsha180920011
47
The slope of line 3X+Y=3 is "-3".
So, the slope of line perpendicular to the line 3X+Y=3 is "1/3".
=> The equation of line passing through (2,2) with slope "1/3" is
      Y-2= (1/3).(X-2)
      3Y-6=X-2
      3Y=X+4
 i.e. Y=(X/3)+4/3
this equation is of form Y=mX+c; where m is the slope of line and c is the y-intercept of line.
So, the y-intercept of line is 4/3
The answer is "d)4/3"
Answered by lord75175
6

Answer:

Step-by-step explanation:

The slope of line 3X+Y=3 is "-3".

So, the slope of line perpendicular to the line 3X+Y=3 is "1/3".

=> The equation of line passing through (2,2) with slope "1/3" is

     Y-2= (1/3).(X-2)

     3Y-6=X-2

     3Y=X+4

i.e. Y=(X/3)+4/3

this equation is of form Y=mX+c; where m is the slope of line and c is the y-intercept of line.

So, the y-intercept of line is 4/3

The answer is "d)4/3"

Similar questions