A line passes through (2,2) and is perpendicular to the line 3x+y=3 its y intercept is a) 1/3 b) 2/3 c) 1 d) 4/3
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The slope of line 3X+Y=3 is "-3".
So, the slope of line perpendicular to the line 3X+Y=3 is "1/3".
=> The equation of line passing through (2,2) with slope "1/3" is
Y-2= (1/3).(X-2)
3Y-6=X-2
3Y=X+4
i.e. Y=(X/3)+4/3
this equation is of form Y=mX+c; where m is the slope of line and c is the y-intercept of line.
So, the y-intercept of line is 4/3
The answer is "d)4/3"
So, the slope of line perpendicular to the line 3X+Y=3 is "1/3".
=> The equation of line passing through (2,2) with slope "1/3" is
Y-2= (1/3).(X-2)
3Y-6=X-2
3Y=X+4
i.e. Y=(X/3)+4/3
this equation is of form Y=mX+c; where m is the slope of line and c is the y-intercept of line.
So, the y-intercept of line is 4/3
The answer is "d)4/3"
Answered by
6
Answer:
Step-by-step explanation:
The slope of line 3X+Y=3 is "-3".
So, the slope of line perpendicular to the line 3X+Y=3 is "1/3".
=> The equation of line passing through (2,2) with slope "1/3" is
Y-2= (1/3).(X-2)
3Y-6=X-2
3Y=X+4
i.e. Y=(X/3)+4/3
this equation is of form Y=mX+c; where m is the slope of line and c is the y-intercept of line.
So, the y-intercept of line is 4/3
The answer is "d)4/3"
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