Question

a line passes through the point (-10,9) and has a slope of -3/2. What is an equation in point slope form for this line?

Answer 1

We know that:

Equation of a line is

(y-b) = slope×(x-a); where a and b are points (a,b)

Here, slope = -3/2 and point = (-10,9)

Let's put them in formula:

$(y - 9) = \frac{ - 3}{2} (x - ( - 10))$

$= > (y - 9) = \frac{ - 3}{2} (x + 10)$

$= > 2(y - 9) = - 3(x + 10)$

$= > 2y - 18 = - 3x - 30$

$= > 3x + 2y - 18 + 30 = 0$

$= > 3x + 2y + 12 = 0$

Hence, this is the required equation of the line.

Answer 2

Given above there is ur answer