Question

A line passing through the points ( a ,2a ) and ( -2 , 3 ) is perpendicular to line 4x + 3y +5 = 0 , then find the value of a .

Answer 1

Heya.....!!!

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Let m1 be the slope of line that is joining the points ( a , 2a ) say point A and ( - 2 , 3 ) say B .

Then m1 is = ( 2a - 3 )/( a + 2 )

=> Let m2 be the slope of the line = 4x + 3y + 5 = 0
Then , m2 = - 4/3 .

=> Now it is given that the 2 lines are perpendicular to esch othevthe we know that

=>> m1 × m2 = - 1

=> Putting the values of m1 and m2 we get ,,

=> (2a-3)/a+2 × - 4/3 = -1

=> 8a - 12 = 3a + 6

➡➡=> a = 18/5 .

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Hope It Helps You ^_^

Answer 2

Answer:

:

Let m1 be the slope of line that is joining the points ( a , 2a ) say point A and ( - 2 , 3 ) say B .

Then m1 is = ( 2a - 3 )/( a + 2 )

=> Let m2 be the slope of the line = 4x + 3y + 5 = 0

Then , m2 = - 4/3 .

=> Now it is given that the 2 lines are perpendicular to esch othevthe we know that

=>> m1 × m2 = - 1

=> Putting the values of m1 and m2 we get ,,

=> (2a-3)/a+2 × - 4/3 = -1

=> 8a - 12 = 3a + 6

➡➡=> a = 18/5 .