Question

A line pq 70 mm long has its end p in the vp and q in the hp the line is inclined at 30°to hp and 60° to vp

Answer 1

Answer:

Given Data:-

True Length (TL) = a’b1’ = ab2 = 70 mm

A is 10 mm above HP = a’ (↑) = 10 mm

A is 15 mm in front of VP = a (→) = 20 mm

θ = 30°

Φ = 60°

Point B is in 3rd quadrant.

Follow the procedure step by step to draw the projection of line –

Draw XY line.

Mark a’ and a at 10 mm above XY line and 20 mm below XY line respectively.

Draw horizontal line from a’ and a.

Draw a line of true length (TL) = 60 mm from point a’ at an angle of 25° (a’b1’). Since point B is in 3rd quadrant Point b1 will be below the XY and poin b2 will be above the XY line.

Draw a line of true length (TL) = 60 mm from point a’ at an angle of 40° (ab2).

Take the projection of b1’ into TV (Draw a vertical line from point b1’) which will cut the horizontal line passing through point a . Mark that point b1, ab1 is your plan length (PL).

Take the projection of b2 into FV (Draw a vertical line from point b2) which will cut the horizontal line passing through point a’ . Mark that point b2’, a’b2’ is your elevation length (EL).

Draw a horizontal line from point b1’, that is your locus of b’.

Draw a horizontal line from point b2, that is your locus of b.

Taking a’ as center and a’b2’ as radius draw an arc which will cut the locus of b’, mark that point b’.

Join a’b’, that is your FV.

Taking a as centre and ab1 as radius draw an arc which will cut the locus of b, mark that point b.

Join ab, that is your TV.