A line PQ 70 mm long is inclined at 30 degree to H.P. and 45 degree to V.P. The length of the line seen in the top view will be (1 marks)
Ans.
1 Greater then AB
2 Smaller then AB
3 None of these
4 Equal to AB
Answers
Answer:
A line PQ 70 mm long is inclined at 30 degree to H.P. and 45 degree to V.P. The length of the line seen in the top view will be (1 marks)
Ans.
1 Greater then AB
2 Smaller then AB
3 None of these
4 Equal to AB
Explanation:
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The length of the line seen in the top view will be (2) Smaller than AB
Given,
Inclination to HP = 30 degrees
Inclination to VP = 45 degrees
To Find,
The length of the line seen in the top view in comparison with AB
Solution,
The vertical plane (VP) is believed to be positioned vertically. This plane receives a projection of the object's front.
The horizontal plane (HP) is believed to be positioned horizontally. It is projected onto this plane from the object's top view.
We have been given that the line PQ is inclined at 30 degrees to HP.
Therefore, cos30 = HP/AB
⇒ √3/2 = HP/AB
⇒ HP = 0.866 AB
⇒ HP < AB
Correction in question: A line AB 70 mm long is inclined at 30 degrees to H.P. and 45 degrees to V.P. The length of the line seen in the top view will be (1 mark)
Ans.
1 Greater than AB
2 Smaller than AB
3 None of these
4 Equal to AB
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