Question

a line segment ab 5cm take a point p not lying on the line construct a perpendicular on line ab from p​

Answer 1

Answer:

1. Draw a line segment AB = 5 cm.

2. With any radius greater than 2.5 cm, and compass fixed at A, draw 2 arcs, one above and one below AB.

3. With the same radius, compass at B, cut the 2 arcs drawn in step 2.

4. The line joining these two arcs is the perpendicular bisector of AB.

i.e. CD is the perpendicular bisector of AB.

Answer 2

Answer:

steps for construction

· draw AB=5cm

· with A as centre cut an arc of 3cm on AB and mark it C

· with A as centre and radius 2.5cm, draw an arc and mark it O

· with O as centre and radius 2.5cm, draw a circle so that points A and C lie on the circle formed

· join OB

· draw perpendicular bisector of OB to obtain mid point of OB, M

· with M as the centre and radius equal to OM, draw a circle to cut the previous circle at point P and Q

· join PB and QB, PB and QB are required tangents to the given circle from exterior point B

QB=PB=3cm

The length of the tangents is 3cm

MARK ME AS BRAINLIST ANSWER

Step-by-step explanation: