A line segment AB=8 cm is divided in the ratio 3:2 by a ray at point P lies on AB . The distance of point P from A is
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Answer:
Step-by-step explanation:
3x 2x A_________________________P_____________B
<……………………………………8 cm…………..............................>
A line segment AB = 8cm is divided in the ratio 3:2 by a ray at point P lies on AB
So AP = 3x, PB = 2x
3x + 2x = 8cm. x = 8/5
The distance of point P from A = 3x = 3*8/5
= 24/5 or 4.8cm Ans
The distance of point P from A is 4.8 cm
it is given that,
a line segment AB=8 cm is divided in the ratio 3:2 by a ray at point P lies on AB.
A.................................P...........................B
let proportionality constant is x.
then, AP = 3x and PB = 2x
as AP + PB = AB = 8cm
⇒3x + 2x = 8
⇒x = 8/5 = 1.6
now, the distance of point P from A = AP = 3x = 1.6 × 3 = 4.8 cm
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