A line segment AB=8cm is divided in the ratio 3:2 by the ray at point P lies on AB. Find the distance of point P from A.
Answers
Answer:
The length of AP' is 4.8 cm.
Step-by-step explanation:
It is given that a line segment AB= 8cm is divided in the ratio 3:2 by a ray at point P' lies on AB.
Point P' lies on the line segment AB. It means point P' divides the line AB in two parts AP' and P'B.
Let length of AP' and P'B are 3x and 2x respectively.
AB=AP'+P'BAB=AP′+P′B
8=3x+2x8=3x+2x
8=5x8=5x
Divide both sides by 5.
\frac{8}{5}=x58=x
The value of x is 8/5.
The length of AP' is
AP'=3x=3\times \frac{8}{5}=4.8AP′=3x=3×58=4.8
Therefore, the length of AP' is 4.8 cm.
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Answer:
AP=4.8cm
Step-by-step explanation:
AB..8CM
ratio=3:2
lenght of AP be 3x and BP be 2x
AB=AP+BP
8=3x+2x
8=5x
Divide both sides by 5
8/5=5x/5
x=8/5
AP=3x=3×8/5=24/5=4.5cm