A line segment AB is bisected at P. What is the measure of AP?
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Answer:
Given: PQ bisects AB and PQ⊥AB
Construction: Join QA and QB
To prove: QA=QB
In △QAP and △QBP
∠QPA=∠QPB (Each 90
∘
)
PA=PB (PQ bisects AB)
PQ=PQ (Common)
thus, △QAP≅△QBP (SAS rule)
Thus, QA=QB (By cpct)
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