A line segment AB is increased along it’s length by 25%by producing it to c on the side of B .if A and B have the co ordinate (1,2)and(5,6) respectively then find the co ordinate of c.
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Answer:
d(A,B) = √ (5-1)² + (6-2)²
= √ 16 + 16
= 4√2
d(B,C) = 25 % d(A,B)
= 25/100 x 4√2
= √2
d(A,C) = d(A,B) + d(B,C)
=4√2 + √2
= 5√2
now , taking B as a point on line AC ,
AB : AC 4 : 1
m:n = 4:1
By section formula
x = mx2+ nx1/m+n
5 = 4(x2) + 1 / 4+1
25 = 4x2 + 1
x2 = 6
y = my2 + ny1/m+n
6 = 4(y2) + 2/4+1
6 = 4y2 + 2 /5
30 = 4y2 + 2
y2 = 7
co-ordinate of point C = (x2,y2) = (6,7)
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