Question

A line segment has two end-points M(3, 7) and
N(11, -6). Find the coordinates of the point w
that lies on the y-axis such that W is equidistant
from M and from N.
Hint: The term 'equidistant' means 'same distance'.​

Answer 1

Answer:

Step-by-step explanation:

w lies on y axis so x will be o then,

MW^2=NW^2

9+(Y-7)^2=121+(Y+6)^2

by solving you will get answer good luck

Answer 2

M(3,7), N(11,-6)

MW=NW

√((3-0)^2 + (7-y)^2)=√((1-0)^2+(y+6)^2)

√(9+49+y^2-14y)=√(121+y^2+36+6y)

take square on both sides

y^2-14y+58=y^2+6y+157

-14y-6y=157-58

-20y=99

y= -99/20

y= -4.95

W(0,-4.95)