a line segment is of length 10 units and one of its and is (- 2,3) if the ordinate of the other end is 9 then determine the absicca of the other end
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Distance between two points =
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
Given, one point =(2,−3)
Let, other point =(10,b)
absicca is x cordinate
∴
(10−2)
2
+(b+3)
2
=10
8
2
+(b
2
+9+6b)
=10
Squaring both the sides, we get
64+b
2
+9+6b=100
(b+3)
2
=36
∴ b+3=6 and b+3=−6
∴ b=3 and b=−9
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