Question

A line segment is of length 10units.If the coordinate of it's one end are (2,-3)and the absicca of the other end is 10,then it's ordinate is..?​

Answer 1

Answer:

Distance between two points  =  

(x  

2

​  

−x  

1

​  

)  

2

​  

 

+(y  

2

​  

−y  

1

​  

)  

2

​  

 

 

​  

 

Given, one point =(2,−3)

Let, other point =(10,b)

absicca is x cordinate

∴  

(10−2)  

2

+(b+3)  

2

 

​  

=10

8  

2

+(b  

2

+9+6b)

​  

=10

Squaring both the sides, we get

64+b  

2

+9+6b=100

(b+3)  

2

=36

∴ b+3=6 and b+3=−6      

∴ b=3 and b=−9