Question

a line segment isof length 10units and one end is (2,-3). if the abscissa of the other end is 10. then it ordinate is​

Answer 1

Answer:

Let the line segment be ABLE

Then according to the question

AB = 10 units

also, A ( 2,-3)

and B( 10,x)

Now by distance formula

AB = √(x1 - x2) ^2 + ( y1 - y2) ^2

10 = √ ( 10-2)^2 + (x+3)^2

on squaring both sides

100 = 64 + x^2 + 9 + 6x

100 = 73 + x^2 + 6x

x^2 + 6x = 27

x^2 + 6x - 27 = 0

x^2 + 3x - 9x - 27 = 0

x(x+3) -9(x+3) = 0

(x+3)(x-9) =0

Therefore

x=-3

or x=9

so, the B can be (10,-3) or (10,9)

Hope this helps you