Question

A line segment joins p(5, 7) and Q(x, y). The midpoint of the line segment is (4, 2). Find the coordinates of Q and the equation of perpendicular bisector of PQ

Answer 1

Answer:

Step-by-step explanation:mid point of line segment=5+x/2 which is equal to 4.

5+x=8

x=3

Similarly, 7+y/2=2

7+y=4

y=-3

For finding equation,firstly find the slope which is 5 because-3-7/3-5 gives -10/-2=5

Equation for perpendicular bisector is y-y1=m(x-x1)

Y-7=5(x-5)

Y-7=5x-25

Y+18=5x

Hope this helps you dear

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