Question

A line segment of 1 metre length is divided into two parts such that the first part is 2/3 of second part. Find the lengths of two parts in centimeter.

Answer 1

Answer: First part is 40 cm and second part is 60 cm

Step-by-step explanation:

Length of the line segment = 1 m = 100 cm

Let the second part be x,

So, the first part = 2/3 of x = 2x/3

A.T.Q,

2x/3 + x = 100

or,(2x + 3x)/3 = 100

or, 5x = 100 x 3

or, 5x = 300

or, x = 300/5

or, x = 60

Second part is 60 cm and first part is = (2 x 600)/3 = 40 cm

Answer 2

Answer:

The length of 1st part will be 40cm and 2nd part will be 60cm.

Step-by-step explanation:

Let the length of the 2nd part of the line segment= x

According to the question,

Length of line segment= 1m

= 100cm

Length of 2nd part= x

Length of 1st part= $\frac{2}{3}$ of x

Hence the equation is,

x+ $\frac{2}{3}$ of x= 100

=> x+ $\frac{2×x}{3}$= 100

=> x+ $\frac{2x}{3}$= 100

=> $\frac{3x+ 2x}{3}$= 100

=> $\frac{5x}{3}$ = 100

=> ${5x}$= 100×3

=> x= $\frac{100×3}{5}$

=> 60

The length of second part is 60cm

So,the length of 1st part will be

$\frac{2}{3}$ of 60

= $\frac{2×60}{3}$

= 40