Question

a line segment of length 3.5 cm was measured 3.55 cm by mistake. find the error percentage.

please say the answer, it's urgent ​

Answer 1

Actual length=3.5cm

Measured length(by mistake)=3.55cm

Error Percentage=

$\frac{measured - actual}{actual} \times 100$

$\frac{3.55 - 3.5}{3.5} \times 100$

$\frac{0.05}{3.5} \times 100$

1.42%

Hope this helps you army.

Answer 2

Answer:

Error percentage = (B-A)×100/A

Here, mistaken value = B

Original value = A

So, (3.55-3.5)×200/3.5

= 5/3.5 = 1.427%