Question

A line that passes through the point (x,y), with a y-intercept of b and a slope of m, can be represented by the equation y = mx + b.

A line is drawn on the coordinate plane that passes through the point (3,-6) and has a slope of 4. The y-intercept of the line is

Answer 1

Answer:

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + by=mx+b

Where:

m: It's the slope

b: It is the cut-off point with the y axis.

On the other hand, the pending point equation is given by:

(y-y_ {0}) = m (x-x_ {0})(y−y

0

)=m(x−x

0

)

Where:

m: It's the slope

(x_ {0}, y_ {0}):(x

0

,y

0

): It is a point through which the line passes.

According to the data we have:

\begin{gathered}(x_ {0}, y_ {0}) :( 10,1)\\m = -0.5\end{gathered}

(x

0

,y

0

):(10,1)

m=−0.5

So:

\begin{gathered}(y-1) = - 0.5 (x-10)\\y-1 = -0.5x + 5\\y = -0.5x + 5 + 1\\ = -0.5 + 6\end{gathered}

(y−1)=−0.5(x−10)

y−1=−0.5x+5

y=−0.5x+5+1

=−0.5+6

Explanation:

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