A line with a slope of -2 crosses the y-axis at (0, 3). The equation of the line _
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m = slope = -2
point (0,3)
The equation of line in slope intercept form is
y = mx + c
c is y intercept
at -2 it crosses y -axis..so y intercept = 3
so the equation will be ..
y = -2(x) + 3
y = -2x + 3
2x +y -3 =0
point (0,3)
The equation of line in slope intercept form is
y = mx + c
c is y intercept
at -2 it crosses y -axis..so y intercept = 3
so the equation will be ..
y = -2(x) + 3
y = -2x + 3
2x +y -3 =0
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