A line with the inclination 4 5° drawn through point A( 4 ,- 5 )and coordinates of two points on this line which are at a distance of 3√2 units from the given points A are
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Step-by-step explanation:
If the line is inclined at angle 45
o
with the positive direction of the x-axis, i.e. the points are situated at angles θ=45
o
from x-axis at a distance r=3
2
from (4,−5)
The two points can be given by (x
0
±rcosθ,y±rsinθ)
The points are (4+3
2
cos45
o
,−5+3
2
sin45
o
)=(4+3
2
×
2
1
,−5+3
2
×
2
1
)=(7,−2)
and
(4−3
2
cos45
o
,−5−3
2
sin45
o
)=(4−3
2
×
2
1
,−5−3
2
×
2
1
)=(1,−8)
Thus, the points are (1,−8) & (7,−2)
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Answer:
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