A linear aperture whose width is 0.02 C is placed immediately in front of a lens e focal length 60 cm. The aperture is
illuminated normally by a parallel beam d wavelength 5 x 10^-5 cm. The distance of
the first dark band of the diffraction pattern from the centre of the screen is
Answers
Answered by
17
Q}____?
=> 0.015 cm
Explanation:
Key idea Ist minima is formed at a distance
Y = λD/a
For the distance of the first dark band of the diffraction pattern from the centre of the screen is given by positon of Ist minima
i.e Y = λD/a
Where
λ = Wavelength of parallel beams
D = focal length
a = width of linear aperture
=>Y =[ ( 5× 10^-5 ) ( 0.6 ) ] / (0.02 × 10^-2
...[Given]
=>Y = 0. 15 cm
The Distance of First dark band of diffraction pattern from the centre of the screen is 0.15 cm !
Answered by
0
f=D=60 cm
For first minima,
y=aλD=2×10−2×10−25×10−7×60=0.15 cm
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