A linear harmonic oscillator of force constant 2×10^6 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its
A P.E. is 160 J
B P.E. is zero
C P.E. is 100 J
D P.E. is 120 J
My doubt is that if the body is at amplitude then it possesses maximum potential energy i.e. total energy is equal to potential energy at amplitude... then the answer should be 'A' ?
Answers
Answered by
0
Answer:
ANSWER
As, we know total mechanical energy = maximum potential energy
∴ATQ.T.E=160J⇒Max.P.E.=160J
⇒ Statement (C) is correct.
Also, for maximum kinetic energy, we know,
K.E.=
2
1
K(x
m
2
)
where x
m
=(0.01)m&K=2×10
6
Nm
−1
⇒K.E.=(
2
1
)(2×10
6
)(0.01)
2
=100J
⇒ Statement (B) is the correct answer.
Explanation:
I hope I help you
....have a nice day ....
Answered by
0
Answer:
B P.E. is zero
Explanation:
is the best of answer
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