Question

A linear harmonic oscillator of force constant 2 ×
10⁶ N/m and amplitude 0.01 m has a total
mechanical energy of 160 J. Its
(a) maximum potential energy is 160 J
(b) maximum potential energy is not 100 J
(c) minimum potential energy is zero
(d) minimum potential energy is 100 J

Answer 1

Nice Question mate !!!

Maximum potential energy = 1/2 k a²

                                              = 1/2 x 2 x 10⁶ x 10 ⁻⁴

                                              = 100 J

Minimum kinetic energy = Total energy - Max potential energy

                                         = 160 - 100

                                         = 60 J

:) Hope this helps !!!

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