Question

A linear object of 10 cm length lies along the axis of a concave mirror of radius of curvature
30 cm, the nearer end lying 18 cm from the mirror. The magnification produced is:

Answer 1

Answer:

Explanation:

The situation is shown in ure. The radius of curvature of the mirror is r=2f=20cm. Thus, the nearer end B of the rod AB is at the centre of the curvature and hence, its image will be formed at B itself.

we shall now locate the image of A.

Here u=-30 cm and f=-10 cm,. We have

1u+1v=1f

or 1/v=1/f-1/u= 1/(-10cm)-1/(-30cm)=or v=-15cm`

Thus the image of A is formed at 15 cm from the pole. The length of the image is therefore 5.0 cm    

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