CBSE BOARD XII, asked by abhiimanyu7, 16 days ago

a linear programming problem is follows

maximise z : 3x+3y

subject to constraint
x+3y<=60
x+y>=10
x<=y
x&y>=0

in feasible region the maximum valu of z is?

Answers

Answered by ritika20192
1

Answer:

Let Z=3x+9y....

1) Converting inequalities to equalities x + 3y = 60 x 0 60 y 20 0

Points are (0,20),(60,0) x+y=10 x 0 10 y 10 0

Points are (0,10),(10,0) x - y = 0 x 0 10 20 y 0 10 20 Points are (0,0),(10,10),(20,20)

Plot the graph for the set of points

The graph shows the bounded feasible region.

ABCD, with corner points A=(10,0),B=(5,5),C=(15,15) and D=(0,20)

To find maximum and minimum

Corner point Z = 3x + 9y A = (0,10) 90 B = (5,5) 60 C = (15,15) 180 D = (0,20) 180

From the graph maximum value of X occurs at two corner points C(15,5) and D(0,20) with value 180 and minimum occurs at point B(5,5) with value 60

PLEASE MARK ME AS BRAINLIEST..,

Answered by tiwaripoonam9032
0

Answer:

Let Z=3x+9y....

1) Converting inequalities to equalities x + 3y = 60 x 0 60 y 20 0

Points are (0,20),(60,0) x+y=10 x 0 10 y 10 0

Points are (0,10),(10,0) x - y = 0 x 0 10 20 y 0 10 20 Points are (0,0),(10,10),(20,20)

Plot the graph for the set of points

The graph shows the bounded feasible region.

ABCD, with corner points A=(10,0),B=(5,5),C=(15,15) and D=(0,20)

To find maximum and minimum

Corner point Z = 3x + 9y A = (0,10) 90 B = (5,5) 60 C = (15,15) 180 D = (0,20) 180

From the graph maximum value of X occurs at two corner points C(15,5) and D(0,20) with value 180 and minimum occurs at point B(5,5) with value 60

PLEASE MARK ME AS BRAINLIEST..,

Explanation:

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