a linear programming problem is follows
maximise z : 3x+3y
subject to constraint
x+3y<=60
x+y>=10
x<=y
x&y>=0
in feasible region the maximum valu of z is?
Answers
Answer:
Let Z=3x+9y....
1) Converting inequalities to equalities x + 3y = 60 x 0 60 y 20 0
Points are (0,20),(60,0) x+y=10 x 0 10 y 10 0
Points are (0,10),(10,0) x - y = 0 x 0 10 20 y 0 10 20 Points are (0,0),(10,10),(20,20)
Plot the graph for the set of points
The graph shows the bounded feasible region.
ABCD, with corner points A=(10,0),B=(5,5),C=(15,15) and D=(0,20)
To find maximum and minimum
Corner point Z = 3x + 9y A = (0,10) 90 B = (5,5) 60 C = (15,15) 180 D = (0,20) 180
From the graph maximum value of X occurs at two corner points C(15,5) and D(0,20) with value 180 and minimum occurs at point B(5,5) with value 60
PLEASE MARK ME AS BRAINLIEST..,
Answer:
Let Z=3x+9y....
1) Converting inequalities to equalities x + 3y = 60 x 0 60 y 20 0
Points are (0,20),(60,0) x+y=10 x 0 10 y 10 0
Points are (0,10),(10,0) x - y = 0 x 0 10 20 y 0 10 20 Points are (0,0),(10,10),(20,20)
Plot the graph for the set of points
The graph shows the bounded feasible region.
ABCD, with corner points A=(10,0),B=(5,5),C=(15,15) and D=(0,20)
To find maximum and minimum
Corner point Z = 3x + 9y A = (0,10) 90 B = (5,5) 60 C = (15,15) 180 D = (0,20) 180
From the graph maximum value of X occurs at two corner points C(15,5) and D(0,20) with value 180 and minimum occurs at point B(5,5) with value 60
PLEASE MARK ME AS BRAINLIEST..,
Explanation: