Question

A liquid drop falls from rest from a height h and takes T time to reach the ground.What is the height of the drop from ground at time T/3?​

Answer 1

Answer:

h/9

Explanation:

height is H

and time is T

so we know the formula as

s=ut+1/2at²

U is initial velocity

but here the liquid drop is falling from rest

so U=0

taking height as x

x=0*t+1/2at²

here the acceleration is taken over by gravity

hence, x=1/2gt²

time given is T/3

x=1/2g(T/3)²

x=1/2gT²/9

x=1/9*1/2gT²

and now we know 1/2gT² is equal to h

hence,x=h/9

this is the solution.

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