Question

A liquid drop of diameter 'D' is split
into 27 droplets. If T is surface
tension of the liquid the change in
energy is
​

Answer 1

⭐ Answer⭐

Since, the volume of water in both the large drop and small droplets would remain the same, the radius of each small drop is,

1.33πR

3

=27×1.33πr

3

Or, r =

3

R

Now, the change in energy is defined as the surface tension times the change in surface area. Or,

δU=TδA

δA=27×4πr

2

−4πR

2

Substituting r = R/3

δA=8πR

2

Since, surface tension is only a function of the surrounding temperatures, therefore it will remain constant during this change.

Hence, δU=2πD

2

×T

Or, δU=2πTD

2

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