Question

A liquid drop of diameter 'D' is split into 27 droplets. It T is surface tension of the liquid the change in energy is ​

Answer 1

Answer:

        2

2πTD

Explanation:

Since the volume of water in both the large drop and small droplets would remain the same, the radius of each small drop is,  

1.33πR  

3

=27×1.33πr  

3

 

Or, r =  

3

R

​  

 

Now, the change in energy is defined as the surface tension times the change in surface area. Or,  

δU=TδA

δA=27×4πr  

2

−4πR  

2

 

Substituting r = R/3  

δA=8πR  

2

 

Since, surface tension is only a function of the surrounding temperatures, therefore it will remain constant during this change.

Hence, δU=2πD  

2

×T

Or, δU=2πTD  

2