A liquid gives force of 100N over an area of 1sq.cm the pressure excreted by the liquid is.
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Answered by
1
f=100 N
A=1 cm^2=10^-4 m^2
p=f/A
=100/10^-4
=10^6 N/m^2 or pa Ans..........................
Answered by
7
Given :
Force exerted by liquid = 100 N
Area = 1 cm²
Well , the units are in different systems so make them in a common system .
1)
1 Newton = 10^5 dyne
100 Newton= 100×10^5
Now,
As we know ,
Pressure = Force/Area = (100×10^5)/1 = 100×10^5 ba
2)
Force = 10^5 N
Area = 1 cm² = 0.0001 m² = 1× 10^-4
Pressure = Force / Area = 10^5÷ 1×10^-4 = 10^5-(-4) = 10^9 Pa
#Be Brainly !!
Force exerted by liquid = 100 N
Area = 1 cm²
Well , the units are in different systems so make them in a common system .
1)
1 Newton = 10^5 dyne
100 Newton= 100×10^5
Now,
As we know ,
Pressure = Force/Area = (100×10^5)/1 = 100×10^5 ba
2)
Force = 10^5 N
Area = 1 cm² = 0.0001 m² = 1× 10^-4
Pressure = Force / Area = 10^5÷ 1×10^-4 = 10^5-(-4) = 10^9 Pa
#Be Brainly !!
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