A liquid is kept in a cylindrical vessel which is. being rotated about its axis .The liquid rises at the sides Of the radius of the vessel is 0.05m and the speed of rotation is 2 rotations per second, find the difference in the height of the liquid at the centre of the vessel and at its sides. Take g=9.8ms
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Answer:
Change in potential energy = change in angular K.E
Radius, r=0.05m
Speed of revolution, ω=2rev.s
−1
⇒mgh=
2
1
m(rω)
2
⇒h=
2g
ω
2
r
2
=
10
(0.05)
2
(2)
2
=0.02m
Explanation:
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