A liquid is kept in a cylindrical vessel which is rotated about its axis liquid rises at the sides if the radius of the vessel is 0.05 m and the speed of rotation is to revolution per second the difference in the height of the liquid at the centre of the vessel and its sides will be
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At the sides the velocity is higher, so the pressure is lower. But the pressure at a given horizontal level must be equal, therefore the liquid rises away to compensate for this drop of pressure. h=v22g=(rω)22g=(0.05×2×2π)22×10=0.02m.
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