Question

A liquid mixture of volume v has two ingrediants with density a and
b.If density of the mixture is d then mass of the first liquid in mixture

Answer 1

Answer:

The total mass of the mixture is M1 + M2 + M3 + … ... Therefore, the volume of the first liquid of density 2.5 gm/cm3 is V1 = 2m/2.5 cm3.

Answer 2

Mass of the first liquid in mixture is (M₁) = αV(β-σ)/β-α

Given-

• Volume of the mixture = V

• Density of first ingredient = α

• Density of second ingredient = β

• Density of mixture = σ

• Let the mass of first liquid = M₁

• Mass of second liquid = M₂

• Total mass = M₁ + M₂

We know that density is equals to mass per unit volume.

So,

σ = total mass/ V

Vσ = M₁ + M₂

M₂ = Vσ - M₁  -----------(i)

V is total volume so

V = M₁/α + M₂/β

By substituting the value-

σ = M₁ + M₂ / (M₁/α) + (M₂/β)

Substituting the value of M₂ from equation (i) we get

M₁ = αV(β-σ)/β-α