Question

A liquid of density 1.2 ×10³ kg /m³ is filled in a beaker up to depth 50 cm. calculate pressure at the bottom. (g=10m/s²) ​

Answer 1

Yes, 1 atmospheric pressure is equal to 10.33 meter under water.1 atmospheric pressure = 1.01325 bar.For under water pressure is define by this equation,P = density of water * gravitational acceleration * height under water.So for water density is equal to 1000kg/m^3.And value of gravitational acceleration is 9.81 m/s^2.Then we put this values in this equation then, P = 1000*9.81*10.33.Then we get P = 101325 Pa(Pascal).Then for converting Pascal into bar as Pascal * 10^5 = 1 bar.So we get the pressure P = 1.01325 bar.So the 1 atmospheric pressure is equal to under water 10.33 meter height’s pressure.