A liquid of density 800kg m^(-3) is filled in a tank open at the top. The pressure, of the liquid, at the bottom of the tank is 6.4 atmospheres. The velocity of efflux throught a hole at the bottom is (1atmosphere = 10^(5)Nm^(-2))
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Answer:
hello mate..
here's ur answer..
v=sqrt(2gh)
But h rho g = p
:. Hg = (p)/(rho)
:.v=2p/rho
= 2x6.4x10^(5))/(10^(3)
= 40m//s.
hope it helps..
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40 ᴍ/ꜱ ɪꜱ ᴛʜᴇ ᴄᴏʀʀᴇᴄᴛ ᴀɴꜱᴡᴇʀ
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