Question

A liquid of mass 200g exerts a pressure of 0.1 Pa at a bottom of container.what pressure would it exert if the cross section of container is doubled

Answer 1

Answer:

if we changes area height of liquid coloum will changes

as mass and volume constant we can calculate height of 2nd coloum =h(2)

pressure = pgh(1) = 0.1 pascal

    volume of liquid = V = h(1) ×a(1) as volume is constant

                       A(2)× h(2) = V                                 here A(2) = 2a(1)

                      2a(1) ×h(2) = V

                       2a(1) ×h(2)= a(1)×h(1)

                                   h(2) = h(1)/ 2

   som pressure is

                           P = pgh(2)

                           P = pgh(1) /2M                   AS     pgh(1) = 0.1

                           P = 0.1/2

                           P =  0.05 pascal

                         

Answer 2

Answer:

0.05 pascal is the pressure exert