Question

A liquid of mass ‘m’ and specific heat ‘S’ is at a temperature ‘2t’.  If another liquid of thermal capacity 1.5 times, at a temperature of t/3 is added to it, the resultant temperature will be​

Answer 1

Already as we know that

Heat lost by one body = Heat gain by other body

So

m1•C1•ΔT1 = m2•C2•ΔT2

$m(S)(2t-T) = m(1.5S) ( T \: - \frac{t}{3} ) \\ 2t\: - \: T \: = 3 \frac{ T }{2} - \frac{t}{2} \\ 5 \frac{ T }{2} = 5 \frac{t}{2} \\ T \: = t$

so the answer is t

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Extra info - What is temperature ?

Temperature is the measure of heat of a body example It is used when we have fever we measure it.