Physics, asked by Prosnipzz, 2 months ago

A liquid of mass m and specific heat S is at temperature 0°C. Another liquid of mass 2m
and specific heat S/2 is at temperature 38°C. If these two liquids are mixed, the
equilibrium temperature is


just need answer​

Answers

Answered by ItzDinu
1

\huge\mathcal\colorbox{lavender}{{\color{b}{✿Yøur-Añswer♡}}}

\large\bf{\underline{\red{VERIFIED✔}}}

θ= \dfrac{m_1s_1θ_1 + m_2s_2θ_2}{m_1s_1 + m_2s_2} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \\ \\  = \frac{(m \times s \times t) +  (\frac{m}{2} \times 2s  \times 2t) }{(m \times s) + ( \frac{m}{2}  \times 2s)}  \\  \\  =  >  \frac{3mST}{2mS}   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\  =  >  \frac{3}{2}T \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

\boxed{I \:Hope\: it's \:Helpful}

{\sf{\bf{\blue{@ℐᴛz ᴅɪɴᴜ࿐}}}}

Answered by SANDHIVA1974
2

Explanation:

\huge\mathcal\colorbox{lavender}{{\color{b}{✿Yøur-Añswer♡}}}

\begin{gathered}θ= \dfrac{m_1s_1θ_1 + m_2s_2θ_2}{m_1s_1 + m_2s_2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = \frac{(m \times s \times t) + (\frac{m}{2} \times 2s \times 2t) }{(m \times s) + ( \frac{m}{2} \times 2s)} \\ \\ = > \frac{3mST}{2mS} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = > \frac{3}{2}T \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \end{gathered}

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