Question

A liquid of specific gravity 0.8 is flowing in a pipe line with a speed of 2m/s.The K. E per cubic meter of it is ​

Answer 1

Answer:

K.E=1/2×mv×v

m = 0.8

v=2m/s then 1/2×0.8×2×2=1.6

Answer 2

Answer:

Kinetic energy = 3.2 J (Joule )

Explanation:

We have been given by question

Specific gravity = 0.8

Speed  = 2 m / s

Now

We know that

Specific gravity =  $\frac{density\ of\ object}{density\ of\ water}$

$0.8=\dfrac{m}{1}$

mass of the object m = 0 .8

There for we find equation,

$kinetic energy=\frac{1}{2} \times mass\times volume^{2}\\\\=\frac{1}{2}\ 0.8 \times2\2^{3}$

Kinetic energy = 3.2 J ( Joule )