A liquid of specific gravity 1.5 is observed to rise 3.0 cm in a capillary tube of diameter 0.50 mm and the
liquid wets the surface of the tube. Calculate th excess pressure inside a spherical bubble of 1.0 cm
diameter blown from the same liquid. Angle of contact = 0°.
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Answer:
The surface tension of the liquid is
T= 2rhρg = 2(0.025cm)(3.0cm)(1.5gm/cm
3)(980cm/sec 2)
=55dyne/cm
Hence excess pressure inside a spherical bubble
p= R4T
= (0.5cm)4×55dyne/cm
=440dyne/cm 2
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