Question

A liquid p' is 1 3 7 times as heavy as water and water is 1 2 5 times as heavy as another liquid q'. The amount of liquid p' that must be added to 7 litres of the liquid q' so that the mixture may weigh as much as an equal volume of water, will be

Answer 1

Answer:

(4.67) = 14/3 Liter of  liquid p to be added

Step-by-step explanation:

Liquid p is  10/7 times as heavy  as water

water is 7/5 times as heavy as another liquid q

Let say density of q  = 5q

then density of water =  (7/5) 5q  = 7q

then density of Liquid p = (10/7)7q  =  10q

Let say P liter is added to 7  liter of q

Volume = p + 7 liter

Mass = Density * Volume  

mass of P liter of liquid p  = P * 10q = 10Pq

mass of 7 litre of liquid q = 7 * 5q  = 35q

total Mass = 10Pq + 35q

Mass of P + 7 liter of Water  =  (P + 7)7q  = 7Pq + 49q

Equating both Mass

10Pq + 35q  = 7Pq + 49q

=>  3Pq  = 14q

=> P = 14/3 = 4.67

14/3 Liter of  liquid p to be added

Answer 2

Step-by-step explanation:

A liquid P is 1 2/7 times heavier than water. Water is 1 5/7 heavier than liquid Q. How many litres of Q should be mixed with 70L of P,so that the weight of the mixture is equal to the weight of water?