a liquid X of density 3.36 g/cm3 is poured in au tube ,which contains Hg.A nother liquid Y is poured in left arm with height 8 cm.Upper level OF X and Y are same.W hat is the density of Y?
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Answered by
121
Density of liquid X = 3.36 gm
The density of the liquid Y can be calculated using the following formula
HxPxG = HyPyG + hHgPHgg
10 × 3.36 = 8 × Py + 2 × 13.6
33.36 = 8 × Py + 27.2
33.36 - 27.2 = 8 Py
6.16 = 8 Py
6.16 ÷ 8 = Py
0.77 = Py
Therefore the density of liquid will be 0.77 gm/cm³.
The density of the liquid Y can be calculated using the following formula
HxPxG = HyPyG + hHgPHgg
10 × 3.36 = 8 × Py + 2 × 13.6
33.36 = 8 × Py + 27.2
33.36 - 27.2 = 8 Py
6.16 = 8 Py
6.16 ÷ 8 = Py
0.77 = Py
Therefore the density of liquid will be 0.77 gm/cm³.
Answered by
52
Density of liquid X-3.36g/ml
Density of liquid Y-dy
Density of mercury - 13.6
height of liquid X is 10 cm
height of liquid y is 8cm
Hy. Dy. g= hx. dx. g +HmDmg
Dy=60.8/8
=0.77=0.8
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