Question

A liter of air containing 1% Ar is repeatedly passed over hot Cu and hot Mg till no reduction of volume takes place. The final volume of Ar will be?

Answer 1

Answer:

After repeated reduction of air the only and final volume will left will be of argon with 10 mL volume.

Explanation:

Volume of air = 1 L

Volume of the argon in air = 1% of the air Volume

$=\frac{1}{100}\times 1 L=0.01 L = 10 ml$

1 L = 1000 mL

10 mL of argon gas is present in 1 L of air mixture. After passing air onto the hot copper and hot magnesium the other constituent of the air will get reduced beside argon which ales reactive noble gas.

After repeated reduction of air the only and final volume will left will be of argon with 10 mL volume.

Answer 2

Answer:

10 mL

here's the answer and hope this helps you.