a lizard climbs a vertical smooth wall . it climbs 12 meters the first hour and slips 7 meters
Answers
The complete question is:
A lizard climbs a vertical smooth wall. It climbs 12 meters the first hour and slips 7 meters the next hour. If the wall is 37 meters high, the time it would take to reach the top would be?
Given:
Distance climbed by the lizard in a hour = 12 meters
Distance it slips the next hour = 7 meters
Height of the wall = 37 meters
To find:
Time taken by the lizard to reach at the top of the wall.
Solution:
In 2 hours the lizard would climb 12 - 7 meters = 5 meters
The lizard can climb 25 meters in 10 hours
The distance left = 37- 25 meters = 12 meters, in this time the lizard will not slip as it will reach to the top of the wall.
Time taken to climb 12 meters = 1 hour
Total time taken = 10 hours+ 1 hour = 11 hours
Therefore the lizard will reach at the top of the wall in 11 hours.
Given :
A lizard climbs a vertical smooth wall. It climbs 12 meters the first hour and slips 7 meters the next hour.
the wall is 37 meters high,
To Find : the time it would take to reach the top would be
Solution:
Time in hr Height in m
1 12
2 5 ( 12 - 7)
3 17 ( 5 + 12)
4 10 (17 - 7)
5 22 ( 10 + 12)
6 15 (22 - 7)
7 27 ( 5 + 12)
8 20 (27 - 7)
9 32 (20 + 12)
10 25 (32 - 7)
11 37 ( 25 + 12)
Lizard will take 11 hrs to reach top of the wall.
Another way :
As lizard has to reach 37 m so once lizard reach 37 m it would not slip as its top
so last hr after which lizard would not slip will be
when lizard has reached ≥ 37 - 12 m
=> lizard has reached ≥ 25 m
in every two hours lizard go = 12 - 7 = 5 m
in 2 * 5 = 10 hrs lizard will cover 25 m
Hence in 11th hour Lizard will reach at top
25 + 12 = 37 m
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