Question

A load 5kN is to be raised with the help of steel wire. Find the minimum dia. of steel wire if stress is not to exceed 100N/mm2

Answer 1

Answer:

your answer is 7.28 mm

Explanation:

Given data:

P = 5 KN = 5000N

σ = 100MN/m2 = 100N/mm2

Let D be the diameter of the wire

We know that,

σ = P/A σ = P/ (Π/4 × D2)

100 = 5000/ (Π/4 × D2) D

= 7.28 mm