Question

A load 5kN is to be raised with the help of steel wire. Find the minimum dia. of steel wire if stress is not to exceed 100N/mm² ?

Answer 1

Explanation:

w = 5000 N

m = 500 kg

P= F/A

100 = 500 × 10/A

A = 50m^2

2 π ×r = 50

2r = d = 50/π

= 50×7/22

= 350/22

=15.9 ~ 16 m