A load 5kN is to be raised with the help of steel wire. Find the minimum dia. of steel wire if stress is not to exceed 100N/mm² ?
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P = 5 KN = 5000N
σ = 100MN/m2 = 100N/mm2
Let D be the diameter of the wire
We know that, σ = P/A
σ = P/ (Π/4 × D2)
100 = 5000/ (Π/4 × D2)
D = 7.28
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