Physics, asked by jiya8127, 7 months ago

A load 5kN is to be raised with the help of steel wire. Find the minimum dia. of steel wire if stress is not to exceed 100N/mm² ?

Answers

Answered by Anonymous
0

P = 5 KN = 5000N

 σ = 100MN/m2 = 100N/mm2

 Let D be the diameter of the wire

We know that,  σ = P/A

σ = P/ (Π/4 × D2)

100 = 5000/ (Π/4 × D2)

D  = 7.28

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